y^2+7y-44=0

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Solution for y^2+7y-44=0 equation: 



y^2+7y-44=0

a = 1; b = 7; c = -44;
Δ = b2-4ac
Δ = 72-4·1·(-44)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-15}{2*1}=\frac{-22}{2}
=-11
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+15}{2*1}=\frac{8}{2}
=4
$

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